## Question

Number of g of oxygen in 32.2 g Na_{2}SO_{4}. 10H_{2}O is

### Solution

22.4

1 mol Na_{2}SO_{4}.10 H_{2}O = 14 g atoms of (O)

*i.e.,322* g Na_{2}SO_{4}. 10H_{2}O contain (O) = 224 g.

32.2g will contain (O) = 22.4g

#### SIMILAR QUESTIONS

Haemoglobin contains 0.33% of iron by weight. The molecular weight of haemoglobin is approximately 67200. The number of iron atoms (at wt. of Fe = 56) present in one molecule of haemoglobin is

In the reaction, 4 NH_{3} (*g*) + 5 O_{2} (*g*) → 4 NO (*g*) + H_{2}O (*l*), when 1 mole of ammonia and 1 mole of O_{2} are made to react to completion

50mL 10 N H_{2}SO_{4}, 25mL 12 N HCl and 40 mL 5 N HNO_{3} were mixed together and the volume of the mixture was made 1000mL by adding water. The normality of the resultant solution will be :

The number of atoms in 4.25 g of NH_{3} is approximately

A 100mL solution of 0.1 N HCl was titrated with 0.2 N NaOH solution. The titration was discontinued after adding 30mL of NaOH solution. The remaining titration was completed by adding 0.25 N KOH solution. The volume of KOH required for completing the titration is

One mole of calcium phosphide on reaction with excess of water gives

The percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (atomic weight = 78.4). Then minimum molecular weight of peroxidaseanhydrous enzyme is

The percentage of nitrogen in urea is about

How much of NaOH is required to neutralize 1500 cm^{3} of 0.1 N HCl? (Na = 23)

10 dm^{3} of N_{2} gas and 10 dm^{3} of gas X at the same temperature contain the same number of molecules. The gas X is